Simple XmlSerializer

// This is the test class we want to
// serialize:
[Serializable()]
public class TestClass
{
private string someString;
public string SomeString
{
get { return someString; }
set { someString = value; }
}

private List settings = new List();
public List Settings
{
get { return settings; }
set { settings = value; }
}

// These will be ignored
[NonSerialized()]
private int willBeIgnored1 = 1;
private int willBeIgnored2 = 1;

}

// Example code

// This example requires:
// using System.Xml.Serialization;
// using System.IO;

// Create a new instance of the test class
TestClass TestObj = new TestClass();

// Set some dummy values
TestObj.SomeString = "foo";

TestObj.Settings.Add("A");
TestObj.Settings.Add("B");
TestObj.Settings.Add("C");


#region Save the object

// Create a new XmlSerializer instance with the type of the test class
XmlSerializer SerializerObj = new XmlSerializer(typeof(TestClass));

// Create a new file stream to write the serialized object to a file
TextWriter WriteFileStream = new StreamWriter(@"C:\test.xml");
SerializerObj.Serialize(WriteFileStream, TestObj);

// Cleanup
WriteFileStream.Close();

#endregion


/*
The test.xml file will look like this:



foo

A
B
C


*/

#region Load the object

// Create a new file stream for reading the XML file
FileStream ReadFileStream = new FileStream(@"C:\test.xml", FileMode.Open, FileAccess.Read, FileShare.Read);

// Load the object saved above by using the Deserialize function
TestClass LoadedObj = (TestClass)SerializerObj.Deserialize(ReadFileStream);

// Cleanup
ReadFileStream.Close();

#endregion


// Test the new loaded object:
MessageBox.Show(LoadedObj.SomeString);

foreach (string Setting in LoadedObj.Settings)
MessageBox.Show(Setting);